Q: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5? Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}. P(E) = n(E)/n(S) = 9/20.
Solution: Here, S = {1, 2, 3, 4, ...., 19, 20} The correct answer is: C) 9/20
Q: If 75% of a number is added to 75, then the result is the number itself. The number is :
Solution: Let the number be x, Then 75% of x + 75 = x => x - 75x/100 =75 => x = 300 . The correct answer is: C) 300
Q: Today is Monday. After 61 days, it will be :
Solution: Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday. After 61 days, it will be Saturday. The correct answer is: D) Saturday
Q: What was the day on 15th august 1947 ?
Solution: 15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947) Odd days in 1600 years = 0 Odd days in 300 years = 1 46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day Jan. Feb. Mar. Apr. May. Jun. Jul. Aug ( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days. Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days. Hence, as the number of odd days = 5, the given day is Friday. The correct answer is: A) Friday
Q: 405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child recieve ?
Solution: Let the total number of children be x. Then, x * (20% of x) = 405 => x * 20x/100 = 405 15x2 = 405 => x=45 Number of sweets received by each child = 20% of 45 = 9. The correct answer is: A) 9
Q: The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is
Solution: Let the numbers be x and (100-x). Then, x100-x=5*495 => x2-100x+2475=0 => (x-55) (x-45) = 0 => x = 55 or x=45 The numbers are 45 and 55 Required difference = (55-45) = 10 The correct answer is: A) 10
Q: If 7 spiders make 7 webs in 7 days, then 1 spider will make 1 web in how many days?
Solution: Let the required number of days be x. Less spiders, More days (Indirect Proportion) Less webs, Less days (Direct Proportion) Spiders1:7Webs7:1⋮⋮ 7:x => 1 * 7 * x = 7 * 1 * 7 => x= 7 The correct answer is: C) 7
Q: The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. what was the total distance travelled in 12 hours?
Solution: Total distance travelled in 12 hours =(35+37+39+.....upto 12 terms) This is an A.P with first term, a=35, number of terms,n= 12,d=2. Required distance = 12/2[2 x 35+{12-1) x 2]=6(70+23)= 552 kms. The correct answer is: C) 552 kms
Q: Simplify: 1.53 + 4.73 + 3.83 - 3 x 1.5 x 4.7 x 3.81.52 + 4.72 + 3.82 - 1.5 x 4.7 - 4.7 x 3.8 - 1.5 x 3.8
Solution: Apply: a3 + b3 + c3 - 3abca2 + b2 + c2 - ab - bc - ca = a + b + c Hence, the answer is 1.5 + 4.7 + 3.8 = 10. The correct answer is: C) 10
Q: If 75% of a number is added to 75, then the result is the number itself. The number is :
Solution: Let the number be x, Then 75% of x + 75 = x => x - 75x/100 =75 => x = 300 . The correct answer is: C) 300
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