Test-Series - reasoning

Test Number 24/24

Q: How many pairs of letters are there in the word " CASTRAPHONE" which have as many letters between them in the word as in the alphabet?
A. 3
B. 4
C. 5
D. 6
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Test Series 7
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Q: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58
A. A
B. B
C. C
D. D
Solution: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L 

Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

The correct answer is: C) C
Q: In a group of persons travelling in a bus, 6 persons can speak Tamil, 15 can speak Hindi and 6 can speak Gujarati. In that group, none can speak any other language. If 2 persons in the group can speak two languages and one person can speak all the three languages, then how many persons are there in the group ?
A. 21
B. 22
C. 23
D. 24
Solution: Let us assume the two persons who can speak two languages speak Hindi and Tamil.
The third person then speaks all three languages.
Tamil – The number of persons who can speak is 6.
Only Tamil 6 – 2 – 1 = 3 Hindi - The number of persons who can speak is 15. Only Hindi 15 – 2 – 1 12 Gujarati – The number of persons who can speak is 6.
Only Gujarati 6 – 1 = 5 Thus the number of persons who can speak only one language is 3 + 12 + 5 = 20 Number of persons who can speak two languages = 2 Number of the person who speaks all the languages = 1 Total number of persons = 23.
The correct answer is: C) 23
Q: If in a code language, COULD is written as BNTKC and MARGIN is written as LZQFHM, how will MOULDING be written in that code?
A. CHMFINTK
B. LNKTCHMF
C. LNTKCHMF
D. NITKHCMF
Solution: Each letter in the word is moved one step backward to obtain the corresponding letter of the code
The correct answer is: C) LNTKCHMF
Q: In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?
A. 18
B. 36
C. 45
D. None of these
Solution: Let R, G, and B represent the number of balls in red, green, and blue boxes respectively.  
 Then,    R + G + B = 108 ...(i),   G + R = 2B ...(ii)   B = 2R ...(iii)   From (ii) and (iii),
we have G + R = 2x 2R = 4R or G = 3R.  
Putting G = 3R and B = 2R in (i), we get:   R + 3R + 2R = 108 =>  6R = 108 => R = 18.  
Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.
The correct answer is: D) None of these
Q: 
A. 
B. 
C. 
D. 
Solution: 

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