Test-Series - numerical

Test Number 11/39

Q: The maximum gap between two successive leap year is?
A. 4
B. 8
C. 2
D.  1
Solution: This can be illustrated with an example. Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).
The correct answer is: B) 8
Q: In a History examination, the average for the entire class was 80 marks. If 10% of the students scored 35 marks and 20% scored 90 marks, what was the average marks of the remaining students of the class ?
A.  25
B.  50
C. 75
D. 100
Solution: Let the number of students in the class be 100 and let this required average be x. Then, (10 * 95) + (20 * 90) + (70 * x) = (100 * 80) => 70x = 8000 - (950 + 1800) = 5250 => x = 75.
The correct answer is: C) 75
Q: A number when divided by 296 leaves 75 as remainder.When the same number is divided by 37,the remainder will be:
A.  1
B.  3
C.  5
D. 2
Solution: Let the Number be Y. Then  Y = 296 q + 75 = (37 x 8)q +( 37 x 2) + 1 = 37 (8q + 2) + 1 Thus, when the number is divided by 37, the remainder is 1
The correct answer is: A) 1
Q: Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?
A. 30 km/h
B. 15 km/h
C.  25 km/h
D.  20 km/h
Solution: If the speed of the faster horse be fs and that of slower horse be ss then  fs+ss=501=50  and       50ss-50fs=56 Now, you can go through options. The speed of slower  horse is 20km/h Since,   20+30=50 and  5020-5030=56    
The correct answer is: D) 20 km/h
Q: Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is
A.  1.967
B. 1.867
C.  1. 28767
D. 1.567
Solution: required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with à = 60 degrees and r = 3.5cm)34*7*7-3*227*3.5*3.5*60360 sq cm   =34*49-11*0.5*3.5 sq cm   = 1.967 sq cm
The correct answer is: A) 1.967
Q: The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
A. 18
B.  28
C. 38
D. 48
Solution: l2+b2=41 (or)   l2+b2=41   Also, lb=20 l+b2=l2+b2+2lb  = 41 + 40 = 81 (l + b) = 9.  Perimeter = 2(l + b) = 18 cm.
The correct answer is: A) 18
Q: The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?
A.  83.5 km/hr
B. 84.5 km/hr
C.  86.5 km/hr
D. 87.5 km/hr
Solution: Let the speeds of two trains be 7X and 8X km/hr. 8x = 400/4 => x= 12.5 km/hrX=4004=>X=12.5Km/hr So speed of first train is 12.5*7 = 87.5 km/hr
The correct answer is: D) 87.5 km/hr
Q: On a sum of money, the simple interest for 2 years is Rs. 660,while the compound interest is Rs.696.30,the rate of interest being the same in both the cases. The rate of interest is
A. 10%
B. 11%
C.  12%
D. 13%
Solution: Difference in C.I and S.I for 2 years = Rs(696.30-660) =Rs. 36.30.   S.I for one years = Rs330. S.I on Rs.330 for 1 year =Rs. 36.30    Rate = (100x36.30/330x1)% = 11%
The correct answer is: B) 11%

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