Q: A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
Solution: We need to know the S.I, principal and time to find the rate. Since the principal is not given, so data is inadequate. The correct answer is: D) cannot be determined
Q: 36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work ? Let the number of days be x then, 27 : 36 :: 18 : x [Please pay attention, we have written 27 : 36 rather than 36 : 27, in indirect proportion, if you get it then chain rule is clear to you :)] =>27x = 36 * 18 => x = 24 So 24 days will be required to get work done by 27 men. }
Solution: Less Men, means more Days {Indirect Proportion
The correct answer is: A) 24 daysQ: Which of the following fractions is greater than 3 /4 and less than 5 / 6 ?
Solution: 3 /4 = 0.75, 5/6 = 0.833, 1/2 = .5, 2/3 = 0.66, 4/5 = 0.8, 9/10 = 0.9. clearly 0.8 lies between 0.75 and .833. 4/5 lies between 3/4 and 5/6.. The correct answer is: B) 4 / 5
Q: 3 pumps working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
Solution: Let the required no of working hours per day be x. More pumps , Less working hours per day (Indirect Proportion) Less days, More working hours per day (Indirect Proportion) Pumps4 : 3Days1 : 2⋮⋮ 8:x => (4 * 1 * x) = (3 * 2 * 8) => x=12 The correct answer is: D) 12
Q: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17th innings ?
Solution: 16x + 85 = 17(x + 3) x = 34 + 3 = 37 The correct answer is: D) 37
Q: The population of a town was 1,60,000 three years ago, If it increased by 3%, 2.5% and 5% respectively in the last three years, then the present population in
Solution: Present population = 160000 * (1 + 3/100)(1 + 5/200)(1 + 5/100)= 177366. The correct answer is: D) 177366
Q: How many of the following numbers are divisible by 132? 264,396,462,792,968,2178,5184,6336
Solution: 132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also. 264 => 4,3,11(/) 396 => 4,3,11(/) 462 => 11,3 792 => 4,3,11(/) 968 => 11,4 2178 => 11,3 5184 => 3,4 6336 => 4,3,11(/) Required number of numbers=4. The correct answer is: A) 4
Q: A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident
Solution: Let A = Event that A speaks the truth B = Event that B speaks the truth Then P(A) = 75/100 = 3/4 P(B) = 80/100 = 4/5 P(A-lie) = 1-34= 1/4 P(B-lie) = 1-45= 1/5 Now, A and B contradict each other =[A lies and B true] or [B true and B lies] = P(A).P(B-lie) + P(A-lie).P(B) = 35*15+14*45=720 = 720*100= 35% The correct answer is: B) 35/100
Q: A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are :
Solution: Given that the student got 125 marks and still he failed by 40 marks => The minimum pass mark = 125 + 40 = 165 Given that minimum pass mark = 33% of the total mark => total mark =33/100 =165 => total mark = 16500/33 = 500 The correct answer is: A) 500
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