Q: In a race, the odd favour of cars P,Q,R,S are 1:3, 1:4, 1:5 and 1:6 respectively. Find the probability that one of them wins the race.
Solution: P(P)=14,P(Q)=15,P(R)=16,P(S)=17All the events are mutually exclusive hence, Required probability = P(P)+P(Q)+P(R)+P(S) 14+15+16+17=319420 The correct answer is: A) 319/420
Q: A, B, C started a business with their investments in the ratio 1:3 :5. After 4 months, A invested the same amount as before and B as well as C withdrew half of their investments. The ratio of their profits at the end of the year is :
Solution: Let their initial investments be x, 3x and 5x respectively. Then, A:B:C = (x*4+2x*8) : (3x*4+(3x/2)*8) : (5x*4+(5x/2)*8) 20x : 24x : 40x = 5 : 6 : 10 The correct answer is: D) 5 : 6 : 10
Q: A watch gains 5 seconds in 3 minutes and was set right at 8 AM. What time will it show at 10 PM on the same day ?
Solution: The watch gains 5 seconds in 3 minutes = 100 seconds in 1 hour. From 8 AM to 10 PM on the same day, time passed is 14 hours. In 14 hours, the watch would have gained 1400 seconds or 23 minutes 20 seconds. So, when the correct time is 10 PM, the watch would show 10 : 23 : 20 PM The correct answer is: D) 10 : 23 : 20 PM
Q: The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers ?
Solution: Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)] = 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20. Required average = (9.2 / 2) = 4.6. The correct answer is: B) 4.6
Q: The average of 7 consecutive numbers is 20. The largest of these numbers is :
Solution: Let the numbers be x, x + 1, x + 2, x + 3, x + 4, x + 5 and x + 6, Then (x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6)) / 7 = 20. or 7x + 21 = 140 or 7x = 119 or x =17. Latest number = x + 6 = 23. The correct answer is: C) 23
Q: A vessel is filled with liquid, 3 parts of which are water and 5 parts of syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Solution: Suppose the vessel initially contains 8 litres of liquid. Let x litres of this liquid be replaced with water.Quantity of water in new mixture = 3-3x8+xlitres. Quantity of syrup in new mixture = 5-5x8 litres. 3-3x8+x=5-5x8 => 5x + 24 = 40 - 5x => 10x = 16 => x = 8/5 So, part of the mixture replaced = 85×18 = 1/5. The correct answer is: C) 1/5
Q: Find the next number in te given series ? 5, 25, 61, 113, ...
Solution: Here the series follow the rule that 12+22 = 5 32+42 = 2552+62 = 61 72+82 = 113 SO NEXT IS, 92+102 = 181 The correct answer is: B) 181
Q: A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions mad by the larger wheel is:
Solution: Let the required number of revolutions made by larger wheel be x. Then, More cogs, Less revolutions (Indirect Proportion) 14 : 6 :: 21 : x => 14 x x = 6 x 21 x=6*21/14 => x=9 The correct answer is: B) 9
Q: A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
Solution: perimeter of the plot = 2(90+50) = 280mno of poles =280/5 =56m The correct answer is: D) 56m
Q: The ratio of water and alcohol in two different containers is 2:3 and 4:5. In what ratio we are required to mix the mixtures of two containers in order to get the new mixture in which the ratio of alcohol and water be 7:5?
Solution: W1:A1 W2:A2 ..... WN:AN 2 : 3 4 : 5 5 : 7 W1W1+A1 = 25 W2W2+A2=49 WNWN+AN = 512 = 72/180 = 80/180 = 75/180 => 5 : 3 Therefore, the ratio is 5: 3 The correct answer is: B) 5:3
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