Test-Series - numerical

Test Number 4/39

Q: The average of 11 numbers is 10.9. If the average of the first six numbers is 10.5 and that of the last six numbers is 11.4, then the middle number is :

A. 10.5
B. 11.5
C. 12.5
D. 13.5
Solution: Middle numbers  =  [(10.5 x 6 + 11.4 x 6) - 10.9 x 11] = (131.4 - 119-9) = 11.5.
The correct answer is: B) 11.5
Q: If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
A. Sunday
B. Saturday
C. Tuesday
D. Wednesday
Solution: The year 2004 is a leap year.
So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March 2005 will be 1 day beyond the day on 6th March 2004.
Given that, 6th March 2005 is Monday.
6th March 2004 is Sunday (1 day before to 6th March 2005).
The correct answer is: A) Sunday
Q: One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card (Jack, Queen and King only)?
A. 3/13
B. 1/13
C. 3/52
D.  9/52
Solution: Clearly, there are 52 cards, out of which there are 12 face cards.

P (getting a face card) = 12/52=3/13.
The correct answer is: A) 3/13
Q: A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
A. 100 m
B. 150 m
C. 190 m
D. 200 m
Solution: Relative speed of the thief and policeman  =  (11 – 10) km/hr = 1 km/hr 
 Distance covered in 6 minutes  = (1/60) x 6 km   = 1/10 km = 100 m
Therefore, Distance between the thief and policeman = (200 – 100) m = 100 m.
The correct answer is: A) 100 m
Q: 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
A. 10
B. 13
C. 14
D. 15
Solution: Let the required number of days be x.
Less persons, More days (Indirect Proportion) More working hours per day, Less days (Indirect Proportion)
Persons30:39
Working hours/day6:5⋮⋮ 12:x   => 30 * 6 * x = 39 * 5 * 12    => x= 13
The correct answer is: B) 13
Q: The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is
A. 49
B. 154
C. 378
D. 1078
Solution: The diameter is equal to the shortest side of the rectangle.  
So radius= 14/2 = 7cm. 
Therefore,  area of circle =πr2=227×49=154cm2
The correct answer is: B) 154
Q: Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
A. 3/20
B. 29/34
C. 47/100
D. 13/102
Solution: Let S be the sample space.  
Then, n(S) = 52C2=(52 x 51)/(2 x 1) = 1326.  
Let E = event of getting 1 spade and 1 heart.  
n(E)= number of ways of choosing 1 spade out of 13 and 1 heart out of 13 = 13C1*13C1 = 169.  

P(E) = n(E)/n(S) = 169/1326 = 13/102.
The correct answer is: D) 13/102
Q: Find the odd man out. 331, 482, 551, 263, 383, 362, 284
A. 263
B. 383
C. 331
D. 551
Solution: In each number except 383, the product of first and third digits is the middle one.
The correct answer is: B) 383
Q: The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
A.  74
B. 94
C. 184
D. 364
Solution: L.C.M. of 6, 9, 15 and 18 is 90.  
Let the required number be 90k + 4, which is multiple of 7.  
Least value of k for which (90k + 4) is divisible by 7 is k = 4.   =>Required number = (90 x 4) + 4   = 364.
The correct answer is: D) 364
Q: If selling price is doubled, the profit triples. Find the profit percent ?
A. 100%
B. 200%
C. 300%
D. 400%
Solution: Let the C.P be Rs.100 and S.P be Rs.x,
Then The profit is (x-100)
Now the S.P is doubled,
then the new S.P is 2x
New profit is (2x-100)
Now as per the given condition; => 3(x-100) = 2x-100
By solving, we get x = 200
Then the Profit percent = (200-100)/100 = 100
Hence the profit percentage is 100%
The correct answer is: A) 100%

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