Q: The surface area of a cube is 1734 sq. cm. Find its volume
Solution: Let the edge of the cube bea. Then, 6a2 = 1734 => a = 17 cm. Volume = a3 = 173 = 4193 cu.cm The correct answer is: C) 4913 cubic.cm
Q: The distance of the college and home of Rajeev is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed (or increased) speed of Rajeev?
Solution: Let the normal speed be x km/h, then 80x-80(x+4)=1 ⇒x2+4x-320=0 ⇒x (x + 20) - 16 (x + 20) = 0 (x + 20 ) (x - 16) =0 x = 16 km/h Therefore (x + 4) = 20 km/h Therefore increased speed = 20 km/h The correct answer is: D) 20 km/h
Q: In a scheme, a pack of three soaps with MRP Rs.45 is available for Rs.42. If it still gives a profit of 5% to the shopkeeper, then the cost price of the pack is ?
Solution: Given M.P=45,S.P=42, Profit = 0.05 Let C.P=x , Then Profit = (42-x)/x = 0.05=> x = 40. The correct answer is: C) 40
Q: The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and heigh
Solution: Area of the field = Total cost/rate = (333.18/25.6) = 13.5 hectares13.5*10000m2=135000m2 Let altitude = x metres and base = 3x metres.Then, 12*3x*x=135000⇒x2=90000⇒x=300 Base = 900 m and Altitude = 300 m. The correct answers are: A) B, 900;H, 300, 300;H, 900, 600;H, 700, 500;H, 900
Q: The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?
Solution: Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1) Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2) Subtracting (1) From (2), we get : Temp, on 5th day - Temp on 1st day = 8 degrees. Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively. Then, 8x - 7x = 8 or x = 8. Temperature on the 5th day = 8x = 64 degrees. The correct answer is: B) 64 degrees
Q: If 1.5x = 0.04y, then the value of ( (y - x) / (y+x) ) is :
Solution: x / y = 0.04 / 1.5 = 4 / 150 = 2 / 75. = > ( (y - x) / (y+x) ) = (1 - (x / y)) / ( 1 + ( x / y)) = (1 - 2/75) / (1 + 2/75) = 73/77... The correct answer is: A) 73/77
Q: A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. In what ratio will the profit be shared at the end of 3 years ?
Solution: A : B : C = (40000 x 36) : (80000 x 12 + 40000 x 24) : (120000 x 24 + 40000 x 12) = 144 : 192 : 336 = 3 : 4 : 7. The correct answer is: B) 3 : 4 : 7
Q: If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ?
Solution: The original fraction is 2551 × 350+100150+100 = 15/17. The correct answer is: B) 15/17
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