Q: A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:
Solution: C.P = Rs.3000 S.P =Rs. [3600 x 10] / [100+(10 x 2)] = Rs.3000 Gain =0% The correct answer is: A) 0%
Q: The diagonal of the floor of a rectangular closet is 712 feet. The shorter side of the closet is 412 feet. What is the area of the closet in square feet?
Solution: Other side = d2-s2= 2254-814 = 1444 = 6 ft Area of closet = (6 x 4.5) sq. ft = 27 sq. ft. The correct answer is: C) 27
Q: The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Solution: We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.Solving the two equations, we get: l = 63 and b = 40.Area = (l x b) = (63 x 40) = 2520 sq.m The correct answer is: A) 2520
Q: Find out the wrong number in the given sequence of numbers. 5, 16, 6, 16, 7, 16, 9
Solution: Terms at odd places are 5, 6, 7, 8 etc. and each term at even place is 16. So, 9 is wrong. The correct answer is: A) 9
Q: The ratio of efficiency of A is to C is 5:3. The ratio of number of days taken by B is to C is 2:3. A takes 6 days less than C, when A and C completes the work individually. B and C started the work and left after 2 days. The number of days taken by A to finish the remaining work is:
Solution: Given that, 5x-6 =3x => x = 3 Number of days taken by A = 9 Number of days taken by C = 15 B : C Days 2 : 3 Therefore, Number of days taken by B = 10 Work done by B and C in initial 2 days = 2110+115= 1/3 Thus, Rest work =2/3 Number of days required by A to finish 2/3 work = (2/3) x 9 = 6 days The correct answer is: C) 6
Q: A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red
Solution: A red ball can be drawn in two mutually exclusive ways (i) Selecting bag I and then drawing a red ball from it. (ii) Selecting bag II and then drawing a red ball from it. Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore P(E1) = 1/2 and P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7 PAE2 = Probability of drawing a red ball when the second bag has been selected = 2/6 Using the law of total probability, we have P(red ball) = P(A) = PE1×PAE1+PE2×PAE2 = 12×47+12×26=1942 The correct answer is: B) 19/42
Q: 40% of 75 + 80% of 25 = K% of 250 Find the value of K?
Solution: From the given data, 40100 x 75 + 80100 x 25 = K100 x 25030 + 20 = 5K250 x 2 = 5KK = 1005 = 20 The correct answer is: B) 20
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