Q: A train moves with a speed of 108 kmph. Its speed in metres per second is :
Solution: 108 kmph = 108*[5/18] m/sec = 30 m / s. The correct answer is: C) 30
Q: A district has 64000 inhabitants. If the population increases at the rate of 2 * 1/2 % per annum, then the number of inhabitants at the end of 3 years will be :
Solution: Population afer 3 years = 64000 * (1 + 5/(2 *100) )^3 = (64000 * 41/40 * 41/40 * 41/40 ) = 68921.. The correct answer is: B) 68921
Q: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:
Solution: Work done by the waste pipe in 1 minute =115-120+124=115-11120 = -140 [-ve sign means emptying] Volume of 140part = 3 gallons Volume of whole = (3 x 40) gallons = 120 gallons. The correct answer is: C) 120 gallons
Q: In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State ?
Solution: Let the number of candidates appeared from each state be x. In state A, 6% candidates got selected from the total appeared candidates In state B, 7% candidates got selected from the total appeared candidates But in State B, 80 more candidates got selected than State A From these, it is clear that 1% of the total appeared candidates in State B = 80 => total appeared candidates in State B = 80 x 100 = 8000 => total appeared candidates in State A = total appeared candidates in State B = 8000 The correct answer is: B) 8000
Q: If HCF of two numbers is 8,which of the following can never be their LCM?
Solution: 60 is not a multiple of 8 The correct answer is: C) 60
Q: A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.600 more. What was the Sum?
Solution: At 5% more rate, the increase in S.I for 10 years = Rs.600 (given) So, at 5% more rate, the increase in SI for 1 year = 600/10 = Rs.60/- i.e. Rs.60 is 5% of the invested sum So, 1% of the invested sum = 60/5 Therefore, the invested sum = 60 × 100/5 = Rs.1200 The correct answer is: A) Rs.1200
Q: Find the odd man out? 396, 462, 572, 427, 671, 264.
Solution: Here the given series is 396, 462, 572, 427, 671, 264. In all the terms, the middle digit is the sum of first and third digit except 427. So the Odd number in the given series is 427. The correct answer is: C) 427
Q: What decimal of an hour is a second
Solution: 1 / (60 * 60) = 1 / 3600 = .0027 The correct answer is: B) .0027
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