Test-Series - numerical

Test Number 40/39

Q: A man borrowed Rs 24000 from two money lenders. For one loan, he paid 15% per annum and for the other 18% per annum. At the end of one year, he paid Rs 4050. How much did he borrow at each rate ? + { [(24000 – x) * 18 * 1]/100 } = 4050 or 15 x + 432000 - 18x = 405000 or x = 9000. Money borrowed at 15% = Rs 9000 . Money borrowed at 18% = Rs 15000. }
A. Rs.16000
B. Rs.12000
C. Rs.15000
D. Rs.13000
Solution: Let the sum at 15% be Rs x and that at 18% be Rs (24000 - x). {(x * 15 * 1)/100
The correct answer is: C) Rs.15000
Q: How many different four letter words can be formed (the words need not be meaningful using the letters of the word "MEDITERRANEAN" such that the first letter is E and the last letter is R?
A. 59
B. 56
C.  64
D. 55
Solution: The first letter is E and the last one is R.   Therefore, one has to find two more letters from the remaining 11 letters.   Of the 11 letters, there are 2 Ns, 2Es and 2As and one each of the remaining 5 letters.   The second and third positions can either have two different letters or have both the letters to be the same.   Case 1: When the two letters are different. One has to choose two different letters from the 8 available different choices. This can be done in 8 * 7 = 56 ways.   Case 2: When the two letters are same. There are 3 options - the three can be either Ns or Es or As. Therefore, 3 ways.   Total number of possibilities = 56 + 3 = 59
The correct answer is: A) 59
Q: A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge (in metres) is
A. 600
B. 750
C. 1000
D. 1250
Solution: speed    = (5x5/18)m/sec             = 25/18 m/sec. Distance covered in 15 minutes    = (25/18 x 15 x 60)m                                                 = 1250 m.
The correct answer is: D) 1250
Q: In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?
A. 6
B. 12
C. 24
D. 18
Solution: You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither 78 = (41-9) + (22-9) + 9 + neither. Not enrolled students = 24
The correct answer is: C) 24
Q: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
A. 9
B. 9.6
C. 10
D. 10.8
Solution: Relative speed = (60 + 40) km/hr =[ 100 x ( 5 / 18 ) ]m/sec = ( 250 /9 ) m/sec. Distance covered in crossing each other = (140 + 160) m = 300 m. Required time = [ 300 x ( 9/250 ) ] sec = ( 54/ 5 )sec = 10.8 sec.
The correct answer is: D) 10.8
Q: Find the odd man out? 28, 12, 4, 2, -2
A.  -2
B.  2
C.  12
D.  28
Solution: Here the given series 28, 12, 4, 2, -2 follows a pattern that   28 28 - 24 = 28 - 16 = 1212 - 23 = 12 - 8 = 44 - 22 = 4 - 4 = 0 (NOT 2)0 - 21 = 0 - 2 = -2   Hence, the odd man in the given series is 2.
The correct answer is: B) 2
Q: The difference between simple and compound interest compounded annually on a certain sum of money for 2 years at 4% per annum is re.1. the sum is
A. 625
B. 630
C. 640
D. 650
Solution: sum=Rs.x C.I=[x(1+4/100)^2-x]=(676/625x-x)=51/625 S.I=(x*4*2)/100=2x/25 x=625
The correct answer is: A) 625
Q: Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
A. 2:5
B. 3:5
C. 4:5
D. 5:4
Solution: Let the third number be x. Then, first number = 120% of x =120x/100 = 6x/5   Second number =150% of x = 150x/100 = 3x/2 Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5
The correct answer is: C) 4:5

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