Q: A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Solution: Let the side of the square(ABCD) be x meters. Then, AB + BC = 2x metres. AC = 2x = (1.41x) m. Saving on 2x metres = (0.59x) m. Saving % =0.59x2x*100 = 30% (approx) The correct answer is: A) 30
Q: If the radius of a circle is decreased by 50%, find the percentage decrease in its area.
Solution: Let original radius = R. New radius = 50100R= 50100R Original area =R2 and new area = πR2 3πR24*1πR2*100 Decrease in area = πR22=πR24 = 75% The correct answer is: C) 75%
Q: A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?
Solution: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009. Required sale = Rs.[(6500 x 6) - 34009] = Rs. (39000 - 34009) = Rs. 4991. The correct answer is: A) 4991
Q: The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
Solution: Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 = 127. The correct answer is: B) 127
Q: A sum of money lent at compound interest for 2 years at 20% per annum would fetch Rs.482 more, if the interest was payable half yearly than if it was payable annually . The sum is
Solution: Let sum=Rs.x C.I. when compounded half yearly = x1+101004-x=464110000 C.I. when compounded annually =x201002-x=1125 464110000x-1125x=482 => x=20000 The correct answer is: B) 20000
Q: If log 2 = 0.30103, Find the number of digits in 256 is
Solution: log(256) =56*0.30103 =16.85768. Its characteristics is 16. Hence, the number of digits in 256 is 17. The correct answer is: A) 17
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ?
Solution: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100 The correct answer is: A) 100
Q: Gaurav spends 30% of his monthly income on food articles, 40% of the remaining on conveyance and clothes and saves 50% of the remaining. If his monthly salary is Rs. 18,400, how much money does he save every month ?
Solution: Saving = 50% of (100 - 40)% of (100 - 30)% of Rs. 18,400 = Rs. (50/100 * 60/100 * 70/100 * 18400) = Rs. 3864. The correct answer is: A) 3864
Q: What was the day of the week on 17th June, 1998 ?
Solution: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days. Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day. Total number of odd days = (0 + 1 + 2 + 0) = 3. Given day is Wednesday. The correct answer is: C) Wednesday
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