Test-Series - numerical

Test Number 16/39

Q: Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected.
A. 1/63
B. 1/14
C. 2/63
D. 1/9
Solution: Let A be the event that X is selected and B is the event that Y is selected. P(A) = 1/7,  P(B) = 2/9. Let C be the event that both are selected. P(C) = P(A) × P(B) as A and B are independent events:         = (1/7) × (2/9)  = 2/63
The correct answer is: C) 2/63
Q: The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
A. 15
B. 16
C. 18
D. 25
Solution: Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.  S.P. of x articles = Rs. 20.  Profit = Rs. (20 - x).  20-xx*100=25  => 2000 - 100x = 25x  => 125x=2000  => x=16
The correct answer is: B) 16
Q: X and Y invested in a business. They earned some profit which they divided in the ratio of 2 : 3. If X invested Rs. 40,000, the amount invested by Y is :
A. 20000
B. 40000
C. 60000
D. 80000
Solution: Suppose Y invested Rs. y. Then 40000/y = 2/3 or y = 60000 .
The correct answer is: C) 60000
Q: If x is 80% of y, then what percent of 2x is y?
A. 65.5 %
B. 64.5 %
C. 63.5 %
D. 62.5 %
Solution:  x = 80 % of y   => x =(80/100 )y   => y/x = 5/4   Required percentage =  [(y/2x)*100] % = (5/8*100) % =62.5%
The correct answer is: D) 62.5 %
Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ?
A. 20 km
B. 16 km
C. 14 km
D. 10 km
Solution: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.
The correct answer is: D) 10 km
Q: A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:
A. 100 m
B. 75 m
C. 25 m
D. 50m
Solution: When B runs 25 m, A runs 45/2 m   When B runs 1000 m, A runs (45/2*1/25*1000)m = 900 m.   B beats A by 100 m.
The correct answer is: A) 100 m
Q: Bhajan Singh purchased 120 reams of paper at Rs 80 per ream. He spent Rs 280 on transportation, paid octroi at the rate of 40 paise per ream and paid Rs 72 to the coolie. If he wants to have a gain of 8 %, what must be the selling price per ream?
A. 90
B. 89
C. 87.48
D. 86
Solution: Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72). = Rs. (9600 + 280+48 + 72) = Rs, 10000. Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800. Sell Price per ream = Rs. [10800/120] = Rs. 90.
The correct answer is: A) 90

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