Q: 7 9 19 18 31 29 Find the odd number in the given Number Series?
Solution: Here the given number series follows a pattern of two alternate series. 1. 7 19 31 ...(Difference of 12) 2. 9 18 27 ...(Difference of 9) Here the odd number is 29 instead of 27 And the next number is 31 + 12 = 43 & 27 + 9 = 36 The correct answer is: B) 29
Q: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
Solution: We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys). Required number of ways = 6C1*4C3+6C2*4C2+6C3*4C1+6C4 = 6C1*4C1+6C2*4C2+6C3*4C1+6C2 = 209. The correct answer is: A) 209
Q: In what time will Rs. 1000 become Rs. 1331 at 10% per annum compounded annually?
Solution: Principal = Rs. 1000; Amount = Rs. 1331; Rate = 10% p.a. Let the time be n years. Then,[ 1000 (1+ (10/100))^n ] = 1331 or (11/10)^n = (1331/1000) = (11/10)^3n = 3 years The correct answer is: C) 3years QUESTION 26 Not answered Marked out of 1.00 Not flaggedFlag question Question text In a college, t
Q: In a college, the ratio of the number of boys to girls is 8 : 5. If there are 160 girls, the total number of students in the college is
Solution: Let the number of boys and girls be 8x and 5x. Total number of students = 13x = 13 * 32 = 416. The correct answer is: D) 416
Q: The difference between the squares of two consecutive odd integers is always divisible by ?
Solution: Let the two consecutive odd integers be (2x + 1) and (2x + 3)Then, (2x + 3)2 - (2x + 1)2 = (2x + 3 + 2x + 1) (2x + 3 - 2x - 1) = (4x + 4)(2)= 8 (x + 1), which is always divisible by 8 The correct answer is: A) 8
Q: Find the number of bricks, each measuring 24 cm x 12 cm x 8 cm, required to construct a wall 24 m long, 8m high and 60 cm thick, if 10% of the wall is filled with mortar?
Solution: Volume of the wall = (2400 x 800 x 60) cu.cm Volume of bricks = 90% of the volume of the wall = [(90/100) x 2400 x 800 x 60] cu.cm Volume of 1 brick = (24 x 12 x 8) cu.cm Number of bricks = [(90/100) x (2400 x 800 x 60) ]/ (24 x 12 x 8) = 45000 The correct answer is: B) 45000
Q: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs. 5000 ?
Solution: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?Ratio of increase of wages = 22:25Ratio of decrease of labourers = 15:11Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275Final bill = Rs. 5000For 275 ratio wages = Rs. 5000For 1 ratio wages = 5000/275For 330 ratio wages = 5000/275 x 330 = Rs. 6000 The correct answer is: B) Rs. 6000
Q: If the compound interest on a certain sum at 1623% to 3 years is Rs.1270, find the simple interest on the same sum at the same rate and f or the same period
Solution: Let the sum be Rs. x. Then, C.I=x*50300*1003-x=343x216-x=127x216 ⇔127x216=1270 x=2160 Thus, the sum is Rs. 2160 S.I=Rs.2160*503*3*1100=Rs 1080 The correct answer is: A) 1080
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