Test-Series - numerical

Test Number 27/39

Q: If the letters of the word CHASM are rearranged to form 5 letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM ?
A. 32
B. 24
C. 72
D. 36
Solution: The 5 letter word can be rearranged in 5!=120 Ways without any of the letters repeating.The first 24 of these words will start with A.Then the 25th word will start will CA _ _ _. The remaining 3 letters can be rearranged in 3!=6 Ways. i.e. 6 words exist that start with CA.The next word starts with CH and then A, i.e., CHA _ _. The first of the words will be CHAMS. The next word will be CHASM.Therefore, the rank of CHASM will be 24+6+2= 32
The correct answer is: A) 32
Q: The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?
A. 20 m
B. 30 m
C. 40 m
D. 50 m
Solution: Let breadth=x meters.   Then, Length =115x100 meters  Given that, x×115x100=460   => x = 20   Breadth = 20 
The correct answer is: A) 20 m
Q: By selling an article at Rs.800, a shopkeeper makes a profit of 25%.At what price should he sell the article so as to make a loss of 25%?
A. Rs.720
B. Rs.640
C. Rs.540
D. Rs.480
Solution: SP = Rs.800 ; Profit = 25%  CP = SP x 100100+P% = 800 x 100100+25 = 640    Now, CP = Rs.640   Loss = 25% = 25% of Rs.640 = Rs.160   Thus, SP = CP - Loss = Rs.640 - Rs.160 = Rs.480
The correct answer is: D) Rs.480
Q: A is thrice efficient as B and C is twice as efficient as B. what is the ratio of number of days taken by A,B and C, when they work individually?
A. 2:6:3
B. 2:3:6
C. 1:2:3
D. 3:1:2
Solution:  A    :    B    :    C    Ratio of efficiency               3     :    1    :    2    Ratio of No.of days            1/3  :   1/1  :   1/2          or                                       2    :    6    :    3    Hence A is correct.  
The correct answer is: A) 2:6:3
Q: A shopkeeper sells one-third of his goods at a profit of 10%, another one-third at a profit of 20%, and the rest at a loss of 6%.What is his overall profit percentage ?
A. 6%
B. 8%
C. 10%
D. 12%
Solution: Let the shopkeeper buy 300g for Rs.300. Now he sells 100g for Rs.110, another 100g for Rs120, and the rest 100g for Rs94.    Therefore, the total amount he receives = Rs.110 + Rs.120 + Rs.94 = 324.    Therefore, the shopkeeper spends Rs.300 and gets back Rs.324.   Therefore, his profit percentage = 24300x100 % = 8%
The correct answer is: B) 8%
Q: A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
A. 230 m
B. 240 m
C. 260 m
D. 270 m
Solution: Speed =[ 72 x (5/18) ]m/sec= 20 m/sec. Time = 26 sec. Let the length of the train be x metres. Then,[ (x+250)/26 ]= 20 => x + 250 = 520 => x = 270.
The correct answer is: D) 270 m
Q: Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?
A. 10.30
B. 10
C. 8.45
D. 9.30
Solution: Assume both trains meet after x hours after 7 am Distance covered by train starting from P in x hours = 20x km Distance covered by train starting from Q in (x-1) hours = 25(x-1) Total distance = 110 => 20x + 25(x-1) = 110 => 45x = 135 => x= 3 Means, they meet after 3 hours after 7 am, ie, they meet at 10 am
The correct answer is: B) 10
Q: A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?
A. 13/42
B. 17/42
C. 5/42
D. 3/14
Solution: 3 letters can be choosen out of 9 letters in 9C3 ways.   More than one vowels ( 2 vowels + 1 consonant  or  3 vowels ) can be choosen in (4C2*5C1)+4C3 ways   Hence,required probability = 4C2*5C1+4C39C3 = 17/42
The correct answer is: B) 17/42
Q: Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in
A. 6 days
B. 12 days
C. 4 days
D. 3 days
Solution: Let x men can do the in 12 days and the required number of days be z   More men, Less days     [Indirect Proportion]   Less work, Less days     [Direct Proportion  ]  men2x:xwork1:12 :: 12 : z ∴2x×1×z=x×12×12  ⇒z=3
The correct answer is: D) 3 days

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