Q: The last day of a century cannot be
Solution: The correct answer is: C) Tuesday
Q: A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
Solution: The correct answer is: B) gains Rs. 50
Q: When 0.232323.... is converted into a fraction , then the result is
Solution: 0.232323...=0.23 =2399 The correct answer is: C) 23/99
Q: A Shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net Profit or loss that he makes?
Solution: SP of first article = Rs.1000 Profit = 20% CP = SP x 100100+P% = Rs. 25003 SP of Second Article = Rs.1000 Loss = 20% CP = SP x 100100-L% = Rs. 1250 So, Total SP = Rs.2000; Total CP = Rs.6250/3 As the CP is more than SP, he makes a loss. Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3) So, Loss Percent = Lossx100/CP = 4% The correct answer is: A) 4%
Q: The reflex angle between the hands of a clock at 10.25 is
Solution: Angle traced by hour hand in 125/12 hrs = (360/12 * 125/12) = 312102 Angle traced by minute hand in 25 min = (360/60 * 25) = 1500 Reflex angle = 3600-31212-1500=3600-162102=197102 The correct answer is: A) 197 1/2
Q: A container contains 50 litres of milk. From that 8 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container ?
Solution: Given that container has 50 litres of milk. After replacing 8 litres of milk with water for three times, milk contained in the container is: ⇒501-8503 ⇒50×4250×4250×4250 = 29.63 litres. The correct answer is: B) 29.63 litres
Q: A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.630 find the share of A ?
Solution: The ratio of A & B investments = (3x8 + 2x4):(4x8 + 5x4) => 8:13 => 8/21 x 630 = 240. The correct answer is: A) Rs. 240
Q: 4 men can repair a road in 7 hours. How many men are required to repair the road in 2 hours ?
Solution: M x T / W = Constantwhere, M= Men (no. of men)T= Time takenW= Work loadSo, here we applyM1 x T1/ W1 = M2 x T2 / W2Given that, M1 = 4 men, T1 = 7 hours ; T2 = 2 hours, we have to find M2 =?Note that here, W1 = W2 = 1 road, ie. equal work load.Clearly, substituting in the above equation we get, M2 = 14 men. The correct answer is: B) 14 men
| You Have Score | /8 |