Q: The calendar for the year 1993 will be same for the year
Solution: NOTE : Repetition of leap year ===> Add +28 to the Given Year. Repetition of non leap year Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2. Step 2: Add +6 to the Given Year. Solution : Given Year is 1993, Which is a non leap year. Step 1 : Add +11 to the given year (i.e 1993 + 11) = 2004, Which is a leap year. Step 2 : Add +6 to the given year (i.e 1993 + 6) = 1999 Therfore, The calendar for the year 1993 will be same for the year 1999 The correct answer is: A) 1999
Q: There are 7 non-collinear points. How many triangles can be drawn by joining these points?
Solution: A triangle is formed by joining any three non-collinear points in pairs. There are 7 non-collinear points The number of triangles formed = 7C3 = 35 The correct answer is: C) 35
Q: A man went downstream for 28 km in a motor boat and immediately returned. It took the man twice as long to make the return trip. If the speed of the river flow were twice as high, the trip downstream and back would take 672 minutes. Find the speed of the boat in still water and the speed of the river flow.
Solution: Let the speed of the boat = p kmph Let the speed of the river flow = q kmph From the given data, 2 x 28p + q = 28p - q => 56p - 56q -28p - 28q = 0 => 28p = 84q => p = 3q. Now, given that if 283q + 2q + 283q - 2q = 67260=> 285q + 28q = 67260=> q = 3 kmph=> x =3q = 9 kmph Hence, the speed of the boat = p kmph = 9 kmph and the speed of the river flow = q kmph = 3 kmph. The correct answer is: B) 9 km/hr, 3 km/hr
Q: The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is
Solution: Let the sum be Rs. P. Then,[p(1+10/100)2-p]=525 Sum =Rs.2500 S.I.= Rs.(2500*5*4)/100 = Rs. 500 The correct answer is: B) Rs.500
Q: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is
Solution: Speed of the stream = 1Motor boat speed in still water be = x kmphDown Stream = x + 1 kmphUp Stream = x - 1 kmph[35/(x + 1)] + [35/(x - 1)] = 12x = 6 kmph The correct answer is: B) 6 kmph
Q: The difference of two numbers is 14. Their LCM and HCF are 441 and 7. Find the two numbers ?
Solution: Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y Difference = 14 => 7x - 7y = 14=> x - y = 2 product of numbers = product of their hcf and lcm=> 7x * 7y = 441 * 7=> x * y = 63 Now, we havex * y = 63 , x - y = 2=> x = 9 , y = 7 The numbers are 7x and 7y=> 63 and 49 The correct answer is: A) 63 and 49
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