Test-Series - numerical

Test Number 5/39

Q: How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?
A. 36 Kg
B. 42 Kg
C. 54 Kg
D. 63 Kg
Solution: By the rule of alligation: C.P. of 1 kg sugar of 1st kind     
C.P. of 1 kg sugar of 2nd kind        
Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3. 
Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind. 
Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.
The correct answer is: D) 63 Kg
Q: A right triangle with sides 3 cm, 4 cm and 5 cm is rotated the side of 3 cm to form a cone. The volume of the cone so formed is:
A. 12 pi cub.cm
B. 15 pi cub.cm
C. 16 pi cub.cm
D. 20 pi cub.cm
Solution: The correct answer is: A) 12 pi cub.cm
Q: The L.C.M of  22, 54, 108, 135 and 198 is

A. 330
B. 1980
C. 5940
D. 11880
Solution: 22 = 2 x 11  54 = 2×33 108 = 22×33 135 = 33×5  198 = 2×32×11  ∴ L.C.M = 22×33×5×11=5940
The correct answer is: C) 5940
Q: The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
A. Rs.2200
B. Rs. 2400
C. Rs.2000
D. Data inadequate
Solution: Let C.P. be Rs. x.   Then,= >1920-xx*100=x-1280x*100   =>  1920 - x = x - 1280   =>  2x = 3200   =>  x = 1600    Required S.P. = 125% of Rs. 1600 =Rs(125/100*1600) = Rs2000
The correct answer is: A) Rs. 2000
Q: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is
A. 71 km/hr
B. 36 km/hr
C. 35.55 km/hr
D. 71.11 km/hr
Solution: Total time taken    = (160/64 + 160/8)hrs                           = 9/2 hrs. Average speed    = (320 x 2/9) km.hr                         = 71.11 km/hr.
The correct answer is: C) 71.11 km/hr
Q: The G.C.D of 1.08, 0.36 and 0.9 is
A. 0.9
B. 0.108
C. 0.03
D. 0.18
Solution: Given numbers are 1.08 , 0.36 and 0.90  H.C.F of 108, 36 and 90 is 18                  [ ∵ G.C.D is nothing but H.C.F]  Therefore, H.C.F of given numbers = 0.18                 
The correct answer is: C) 0.18
Q: A sum of Rs. 427 is to be divided among A, B and C such that 3 times A’s share, 4 tunes B’s share and 7 times C’s share are all equal. The share of C is :
A. 140
B. 196
C. 240
D. 84
Solution: 3A = 4B = 7C = k,Then A = k/3, B = k/4 and C= k/7. A : B : C = k/3 : k/4 : k/7 = 28:21 :12. Cs share = Rs. [427 x (12/61)] = Rs. 84
The correct answer is: A) 84
Q: In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
A. 1/3
B. 7/21
C. 3/5
D. 8/21
Solution: Total number of balls = (8 + 7 + 6) = 21. Let E = event that the ball drawn is neither red nor green              = event that the ball drawn is blue. n(E) = 7. P(E) = n(E)/n(S) = 7/21 = 1/3.
The correct answer is: A) 1/3
Q: If 20 men can build a wall 56 meters long in 6 days , what length of  a similar wall can be  built by 35 men in 3 days?
A. 46
B. 47
C. 48
D. 49
Solution: Let the required length be x meters  More men, More length built     (Direct proportion)  Less days, Less length built      (Direct Proportion) Men20:35Days6 : 3⋮⋮ 56 :x  => (20 x 6 x X)=(35 x 3 x 56)  => x = 49  Hence, the required length is 49 m.
The correct answer is: D) 49
Q: What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?
A. Rs.550
B. Rs.325
C. Rs.545
D. Rs.560
Solution: Let each instalment be Rs.x .   1st year =  [x + (x * 12 * 2)/100]  2nd year = [ x + (x *12 * 1)/100]  3rd year = x  Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092  3x + ( 24x/100 ) + ( 12x/100 )  = 1092  336x =109200 Therefore, x = 325  Each instalment = Rs. 325
The correct answer is: A) Rs.325

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