Q: The area of a circle of radius 5 is numerically what percent its circumference?
Solution: required percentage = πr22πr×100 =250% The correct answer is: B) 250%
Q: If the number 517?324 is completely divisible by 3,then the smallest whole number in place of ? will be:
Solution: Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = ( 22 + x ), which must be divisible by 3. When x=2. [(22 + 2) = 24 is divisible by 3] So, the answer is 2 The correct answer is: A) 2
Q: Prove that any date in March of a year is the same day of the week corresponding date in November that year
Solution: We will show that the number of odd days between last day of February and last day of October is zero. . March April May June July Aug. Sept. Oct. 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 = 241 days = 35 weeks = 0 odd day. ,Number of odd days during this period = 0. Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows The correct answer is: A) Same day
Q: A motorist travels to a place 150 km away at an average speed of 50 km/hr and returns at 30 km/hr. His average speed for the whole journey in km/hr is :
Solution: Average speed = (2xy) /(x + y) km/hr = (2 * 50 * 30) / (50 + 30) km/hr. 37.5 km/hr. The correct answer is: C) 37.5
Q: A sum of Rs.312 was divided among 100 boys and girls in such a way that the boy gets Rs.3.60 and each girl Rs. 2.40 the number of girls is
Solution: tep (i): Let x be the number of boys and y be the number of girls. Given total number of boys and girls = 100 x+y=100 -------------- (i) Step (ii): A boy gets Rs. 3.60 and a girl gets Rs. 2.40 The amount given to 100 boys and girls = Rs. 312 3.60x + 2.40y = 312 -------------- (ii) Step (iii): Solving (i) and (ii) 3.60x + 3.60y = 360 --------- Multiply (i) by 3.603.60x + 2.40y = 312 --------- (ii) 1.20y = 48 y = 48 / 1.20 = 40 Number of girls = 40 The correct answer is: B) 40
Q: Find the missing number? 15, 30, ? , 40, 8, 48
Solution: Given nuber series is 15, 30, ? , 40, 8, 48 Here the number series follows a pattern that 15 15 x 2 = 30 30 ÷ 3 = 10 10 x 4 = 40 40 ÷ 5 = 8 8 x 6 = 48 Hence, the missing number in the series is 10. The correct answer is: D) 10
Q: In some quantity of ghee, 60% is pure ghee and 40% is vanaspati. If 10 kg of pure ghee is added, then the strength of vanaspati ghee becomes 20%. The original quantity was :
Solution: Let the original quantity be x kg. Vanaspati ghee in x kg = (40x / 100 )kg = (2x / 5) kg. Now, (2x/5)/(x + 10) = 20/100 => 2x / (5x + 50) = 1/5 => 5x = 50 => x = 10. The correct answer is: A) 10 kg
Q: How many arrangements of the letters of the word ‘BENGALI’ can be made if the vowels are to occupy only odd places.
Solution: There are 7 letters in the word Bengali of these 3 are vowels and 4 consonants. There are 4 odd places and 3 even places. 3 vowels can occupy 4 odd places in 4P3 ways and 4 constants can be arranged in 4P4 ways. Number of words =4P3 x 4P4= 24 x 24 = 576 The correct answer is: B) 576
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